Question :- 

A man has three daughters who celebrates their birthday on the same day, but were born in 1977, 1978 and 1979 respectively. On one such birthday, if the product of their ages was divided by their respective ages in turn, the sum of quotients would have been 74. Find the age of the eldest daughter.

a) 6    b) 8    c) 7    d) None of these

If the ages are x, y, z then xyz/y + xyz/z = 74, or xy + yz + zx = 74, where x, y, z are consecutive numbers. Try the alternatives.
Ans: a) 6